ZenHAX

not sure what it is really is called but id like to now how to achieve this by bms script

like if the size it 0xF2DA it will output 0xF300
or if the size it 0x3A2DA it will output 0x3A300


really not sure how to do this

this is my closest miserable attempt to make one but it's still wrong...


set SIZE long 0xF2DA
xmath TEST2 "(SIZE & 0xF00) + 0x100"
xmath TEST3 "(SIZE & 0xF000) + TEST2"


it will output 0xF300 but if I input like 0x2F300 it will still output 0xF300

math SIZE x 0x100

Yeah it's really that easy

here try this

set SIZE long 0x3A2DA
print "%SIZE|hex% :size"
xmath CHECK "SIZE % 256"
print "%CHECK|hex% :check"
if CHECK != 0
   xmath SIZE "(SIZE - CHECK) + 256"
   print "%SIZE|hex% :new size"
endif
print "%SIZE|hex% :final size"

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@Acewell
Why? Isn't "math SIZE x 0x100" better?

.
Could you kindly paste the source code for the math x command? I'd like to port it to a C# tool I'm working on.
Lucky coincidence this showed up on my twitter feed yesterday when I ran into the problem

var1 is the number to round and var2 is the alignment (for example 0x100):

if(var2 && ((u_int)var1 % (u_int)var2)) { var1 += (var2 - ((u_int)var1 % (u_int)var2)); }

Thank you!

oh wait, that "x" is a special operator isn't it?
i was thinking you meant "times", like 2 x 2 = 4

first time i saw that "x" used, you never mentioned this solution to my "maintain a multiple of 4" problem here
viewtopic.php?f=13&t=3952

both ways work, but can you round down with your solution?
ah i see you have a "y" operator for that

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Eh, when I see long posts I can't focus on them and, in that case I just focused only on the script you posted almost ignoring the rest

Anyway you can find all the operators in quickbms.txt, 'x' is there.

thanks for the reply! gonna try some of the examples you guys gave.