Hey guys.
Quick question.
While using fsbext, if it can find a partial password, how many characters should it be? and you count from where?
I have the following results on a file, please advise, if possible, thank you.
Code:
FSB files extractor 0.3.5
by Luigi Auriemma
e-mail: me@aluigi.org
web: aluigi.org
- GUI mode activated, remember that the tool works also from command-line
where are available various options
- select the output folder where extracting the files
- input file: C:\Program Files (x86)\Origin Games\SHIFT 2 UNLEASHED\Audio\Musi
c\drift_music.fsb
- enter folder: C:\Users\User\Desktop\TCWD\fsbext
- probably the file uses encryption, insert the needed keyword:
type ? for viewing the hex dump of the first 176 bytes of the file because
it's possible to see part of the plain-text password in the encrypted file!
?
- encryption type 1
6c ae b4 ae ca 9a 7a c6 24 92 d2 ac c1 27 6b 5a l.....z.$....'kZ
1e ac 56 92 d0 6c d6 e6 91 1a fb e9 f4 39 e6 e6 ..V..l.......9..
35 e8 ec d6 1b 4c 9d 04 bb 54 87 43 e3 b0 52 4f 5....L...T.C..RO
14 ac 54 d8 60 0e fc 1c 20 62 88 40 b2 98 80 c8 ..T.`... b.@....
f4 c6 70 ac 38 68 34 50 ca 32 d2 ac c2 4c 6e 7a ..p.8h4P.2...Lnz
1f da c4 92 f1 0d d4 e6 ac 6e 72 12 da 58 84 56 .........nr..X.V
0e 24 d6 82 c3 47 7a c6 d3 32 d3 ac c3 4c 4e 7a .$...Gz..2...LNz
1e ac 77 6e f2 6e ee 84 a6 6e 72 12 24 2e 36 56 ..wn.n...nr.$.6V
04 64 d4 c8 50 f8 50 3c a0 be 28 3e 84 da 30 fc .d..P.P<..(>..0.
e4 5e 38 04 14 6c d6 e6 ac 6e 72 12 24 2e 36 56 .^8..l...nr.$.6V
0f d5 8c 82 c0 49 08 c6 2c 32 d2 ac 3c fd 14 7a .....I..,2..<..z
- encryption type 2
70 26 6f 33 53 59 5e 63 24 49 4b 35 83 e4 d6 5a p&o3SY^c$IK5...Z
78 35 6a 49 0b 36 6b 67 89 58 df 97 2f 9c 67 67 x5jI.6kg.X../.gg
ac 17 37 6b d8 32 b9 20 dd 2a e1 c2 c7 0d 4a f2 ..7k.2. .*....J.
28 35 2a 1b 06 70 3f 38 04 46 11 02 4d 19 01 13 (5*..p?8.F..M...
2f 63 0e 35 1c 16 2c 0a 53 4c 4b 35 43 32 76 5e /c.5..,.SLK5C2v^
f8 5b 23 49 8f b0 2b 67 35 76 4e 48 5b 1a 21 6a .[#I..+g5vNH[.!j
70 24 6b 41 c3 e2 5e 63 cb 4c cb 35 c3 32 72 5e p$kA..^c.L.5.2r^
78 35 ee 76 4f 76 77 21 65 76 4e 48 24 74 6c 6a x5.vOvw!evNH$tlj
20 26 2b 13 0a 1f 0a 3c 05 7d 14 7c 21 5b 0c 3f &+....<.}.|![.?
27 7a 1c 20 28 36 6b 67 35 76 4e 48 24 74 6c 6a 'z. (6kg5vNH$tlj
f0 ab 31 41 03 92 10 63 34 4c 4b 35 3c bf 28 5e ..1A...c4LK5<.(^
- probably the file uses encryption, insert the needed keyword:
type ? for viewing the hex dump of the first 176 bytes of the file because
it's possible to see part of the plain-text password in the encrypted file!